Question

(b) At what distance from the mirror should screen be placed in order to obtain a sharp image? Find the nature of the image. ​

Answer 1

Answer:

R=2f

30=2f

f=-15cm

u=-25cm

1/v+1/u=1/f

1/v=1/f-1/u

1/v=(1/-15)-(1/-25)

1/v=(-1/15)+(1/25)

1/v=(-5+3)/75

1/v=-2/75

v=-75/2

v=-37.5cm

Screen should be placed at distance of 37.5 cm from the mirror

Nature of image: Real and inverted