Question

[b-(b - x^2)^1/2] / [b (b - x^2)^1/2] = a

Answer 1

let (b - x^2 )^1/2 = r

now,
(b - r)/(br) = a

b - r = abr

b = r (ab + 1)

r =b/(ab +1)
now put r =( b - x^2)^1/2

(b -x^2)^1/2 =b/(ab +1)

take square both side ,
( b - x^2 ) =b^2 /(ab + 1)^2

x^2 = b - b^2/(ab + 1)^2

={b (ab + 1)^2 -b^2}/(ab + 1)^2

take square root both side ,
x = +_root {b (ab +1)^2-b^2}/(ab +1)

Answer 2

hope it helps plzz mark it as brainliest