Math, asked by Anonymous, 1 year ago

Plzz answer the 19th and 20th qn,it's really urgent

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Anonymous: Question no. 20 is creating some issue but I will do it yrrr.. I m missing something in it I guess.

Anonymous: Question no. 20 also done yeah I will try calling u and will tell u how to do it.. Or else I will answer it in eve okay

Anonymous: Both questions are easy I will tell u how to solve it..

sravya5: i got the 20th too.I just substituted in the formula and found the value of tetha same thing for the second part of the question

Answers

Answered by sravya5

working on the second part of the question...

consider tetha as °

area of BOA=1/2×r×AB
=1/2×r?×tan°
=r^2tan°/2.
area of sector OCA=°/360×πr^2
area of shaded region=ar of triangle- ar of sector
=r^2tan°/2-°/360×πr^2
r^2/2{tan°-π°\180}

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Anonymous: Thanks a lot for ur answer..urs too helped me

Answered by Anonymous

Hey sruthi the question is really good. But let me tell you it is really easy one all you need to do is to understand one step in it. I have tried to elaborate it to you so that you don't have any problem. If you still face any doubts pls do contact me. The main step in the 19th question is to get the value of BA which you can get by multiplying tangent of thitha by r, which I have tried to explain in the attachments below hope they will help you. And pls feel free to contact me for any doubts.
Pls mark me as brainliest if you are satisfied by the answers. ☺
Have a great day ahead.

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Anonymous: Thanks adi ....thanks a lot,nikku 20th qn kuratchu stuck aayi pakshe ippol okk.....

Anonymous: As Ur answer helped me a lot,njan thande ans brliest aayittu mark chrydhittindu,thanks a lot ...

Anonymous: Hey it's fine u should always choose the best answer as brainliest

Echo: Great answer bro!!

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