Question

(b+c) /(a-b) (a-c) +(c+a) /(b+a) (b-c) +(a+b) /(c-a) (c-b)

Answer 1

☆Hey friend!!!☆

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Here is your answer ☞
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$\frac{(b + c)}{(a - b)(a - c)} + \frac{(c + a)}{(b - a)(b - c)} + \frac{(a + b)}{(c - a)(c - b)} \\ \\ = \frac{(b + c)}{(a - b)(a - c)} - \frac{(c + a)}{(a - b)(b - c)} + \frac{(a + b)}{(a - c)(b - c)} \\ \\ = \frac{(b + c)(b - c) - (a + c)(a - c) + (a + b)(a - b)}{(a - b)(b - c)(a - c)} \\ \\ = \frac{( {b}^{2} - {c}^{2}) - ( {a}^{2} - {c}^{2} ) + ( {a}^{2} - {b}^{2}) }{(a - b)(b - c)(a - c)} \\ \\ = \frac{ {b}^{2} - {c}^{2} - {a}^{2} + {c}^{2} + {a}^{2} - {b}^{2} }{(a - b)(b - c)(a - c)} \\ \\ = \frac{0}{(a - b)(b - c)(a - c)} \\ \\ = > \: \: infinity \: \: \: \: \: \: .......answer \\ \\ we \: know \: that \: = > \frac{0}{something} \: = \: infinity \: (always)$

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Devil_king ▄︻̷̿┻̿═━一

Answer 2

Answer: here is your answer

Step-by-step explanation: