Question

(b+c-a)tan A/2=(c+a-b)tan B/2(a+b-c)tan C/2​

Answer 1

Answer:

(b + c - a)tanA/2 = (c + a - b)tanB/2

= (a + b - c)tanC/2

b + c - a = 2(s - a)

c + a - b = 2(s - b)

a + b - c = 2(s - c)

r = (s - a)tan(A/2)

Hence Proved.

Step-by-step explanation:

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