b(c-d)^2+a(d-c)+3(c-d)
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Answered by
120
Bonjour!
=> b(c - d)² + a(d - c) + 3(c - d)
=> b(c - d)(c - d) - a(c - d) + 3(c - d)
=> (c - d)(b(c - d) - a + 3)
=> (c - d)(bc - bd - a + 3)
Hope this helps...:)
=> b(c - d)² + a(d - c) + 3(c - d)
=> b(c - d)(c - d) - a(c - d) + 3(c - d)
=> (c - d)(b(c - d) - a + 3)
=> (c - d)(bc - bd - a + 3)
Hope this helps...:)
Answered by
35
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let's, => (c - d) = x
than the equation will be :-
=> (c - d).(bc - bd - a + 3)
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