Math, asked by sushil3827, 1 year ago

b(c-d)^2+a(d-c)+3(c-d)

Answers

Answered by Anonymous
120
Bonjour!

=> b(c - d)² + a(d - c) + 3(c - d)

=> b(c - d)(c - d) - a(c - d) + 3(c - d)

=> (c - d)(b(c - d) - a + 3)

=> (c - d)(bc - bd - a + 3)

Hope this helps...:)
Answered by Deepsbhargav
35
 = > b {(c - d)}^{2} + a(d - c) + 3(c - d) \\ \\ = > b {(c - d)}^{2} - a(c - d) + 3(c - d)
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let's, => (c - d) = x

than the equation will be :-

 = > b {x}^{2} - ax + 3x \\ \\ = > x(bx - a + 3) \\ \\ = > (c - d)[b(c - d) - a + 3]

=> (c - d).(bc - bd - a + 3)
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