B+C
In triangle ABC, show that tan(B+C/2) = cotA/2
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1
Step-by-step explanation:
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Answered by
3
we know that in triangle ABC
angleA+angleB+angleC=180
B+C=180-A
B+C/2=90-A/2
tan(B+C/2)=tan(90-A/2)
cotA/2
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