Question

b) Construct the right-angled ∆PQR, where ⟨Q = 90°, QR = 6 cm and PR = 10 cm.
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Answer 1

Answer:

So Q=90°,QR=6cm and PR=10 cm

so Q,QR,PR=10+6 =16

by pr,qr,and q

16÷90°

so ans 5° and remains 10cm triangle