B) find the cylindrical coordinates of the points where the cartesian coordinates are i) (6,6,8) ii) (✓2,1,1 )
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Given: Cartesian coordinates i) (6,6,8) and ii) (√2,1,1 ).
To find: The cylindrical coordinates of the points.
Solution:
- Now we know that the relation between cartesian coordinate and cylindrical coordinate is:
r² = x² + y²
tanФ = y / x
z = z
(i) x = 6, y = 6, z = 8
r² = (x² + y²)
r = 6√2
Ф = π/4
z = 8
- So the cylindrical coordinates are (6√2, π/4, 8)
(ii) x = √2, y = 1, z = 1
r² = (x² + y²)
r = √3
Ф = 0.615 rad
z = 1
- So the cylindrical coordinates are (√3, 0.615, 1)
Answer:
The cylindrical coordinates of the points where the cartesian coordinates are (6,6,8) is (6√2, π/4, 8) and (✓2,1,1 ) is (√3, 0.615, 1).
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