Question

(b) Find the value of a’ + b² when a + b = 8, ab = 20

But please with all calculations and explanations​

Answer 1

Answer:

Given:

• $a+b=8$
• $ab=20$

Solution:

$a+b = 8$

$\implies (a+b)^2 = 8^2$

$\implies a^2 + 2ab + b^2 = 64$

$\implies a^2 + b^2 + 2(20) = 64$$(\because ab = 20$

$\implies a^2 + b^2 + 40 = 64$

$\implies a^2 + b^2 / 64 - 40$

$\boxed{\implies{\boxed{a^2+b^2 = 24}}}$

Answer 2

Answer:

24

Step-by-step explanation:

we know that a^2 + b^2 = (a+b)^2 - 2ab

so a^2 + b^2 = (8)^2 - 2×20

= 64 - 40

= 24