Question

b) Find the velocity of a bullet of mass 10 gram which is fired from a gun of mass 2.5 kg. The recoil velocity of gun is 2.5 m/s.​

Answer 1

Answer:

Conservation of linear momentum gives,

m  

1

​  

v  

1

​  

+m  

2

​  

v  

2

​  

=0

m  

1

​  

v  

1

​  

=−m  

2

​  

v  

2

​  

 

v  

1

​  

=  

m  

1

​  

 

−m  

2

​  

v  

2

​  

 

​  

 

Given, m  

1

​  

=10g=(  

1000

10

​  

)kg,  

m  

2

​  

=1 kg,

v  

2

​  

=−5m/s

∴v  

1

​  

=  

10/1000

+1×5

​  

 

or v  

1

​  

=500m/s.