Question

B.
For given simultaneous reaction :
X(s) = A(g) + B(s) + C(9) Kp = 500 atma
Y(s) = D(g) + A(g) + E(s) Kp, = 2000 atm2
If total pressure = x, then write your answer after dividing by 25.​

Answer 1

Given:

• The equilibrium constant for decomposition of X (K1) is 500 atm²
• The equilibrium constant for decomposition of Y (k2) is 2000 atm²

To find:

The total pressure at equilibrium divided by 25.

Solution:

• Let the partial pressure of gases formed from decomposition of X be x atm and that from decomposition of Y be y atm.
• P(A) = x+y , P(C) = x , P(D) = y.
• So, we can write, K1 = P(A).P(C) = x(x+y) and K2 = P(A).P(D) = y(x+y)
• Dividing both we get, K2/K1 = y/x = 4. Hence, y = 4x
• Using the relation obtained in K1, we get K1 = x(x+4x) = 5x² ⇒ x = 10atm
• Hence, y = 4x = 40atm
• The total pressure at equilibrium is equal to P(A)+P(C)+P(D) = 2x+2y = 100atm

Answer:

The total pressure at equilibrium divided by 25 is equal to 4.