Question

b) From the sum of 4+3x and 5-4x+2x2, subtract the sum of 3x2-5x and -x^2 +2x+5

Answer 1

Answer:

Solution

verified

Verified by Toppr

given, [(4+3x)+(5−4x+2x

2

)]−[(3x

2

−5x)+(−x

2

+2x+5)]

=(2x

2

−x+9)−(2x

2

−3x+5)

=2x+4

❤≛⃝☆måmtåہہ٨ answer.

Answer 2

From the sum of $4+3x$and$5-4x+2x^{2}$, we have to subtract the sum of $3x^{2} -5x$and$-x^{2} +2x+5$.

By using the Bodmas rule, we are solving the above equation.

As we know that the Bodmas rule is used to remember the order of operations to be followed while solving expressions in mathematics.

Where,

$\begin{array}{l}\mathrm{B}=\text{brackets}\\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$

We are solving in the following way:

Now, the sum of $4+3x$and$5-4x+2x^{2}$ will be:

$=>4+3x+5-4x+2x^{2} \\=>9-x+2x^{2}\\=>2x^{2}-x+9$

Hence, the sum of $4+3x$and$5-4x+2x^{2}$ is$2x^{2}-x+9$.

Now the sum of $3x^{2} -5x$and$-x^{2} +2x+5$ will be:

$=>3x^{2} -5x+(-x^{2} +2x+5)\\=> 3x^{2} -5x-x^{2} +2x+5\\=>2x^{2}-3x+5$

Hence, the sum of $3x^{2} -5x$and$-x^{2} +2x+5$ is$2x^{2}-3x+5$.

Now, subtracting$2x^{2}-3x+5$ from$2x^{2}-x+9$:

=> $2x^{2}-x+9$-$2x^{2}-3x+5$

$=> 2x^{2} -x+9-2x^{2} +3x-5\\=>2x+4$

Hence, after subtracting$2x^{2}-3x+5$ from$2x^{2}-x+9$ we get the solution is$2x+4$.