(b) From the top of a cliff the angle of depression to a boat 200 m far away from The cliff is found to be 30°. Find the height of the cliff.
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Let x1 = distance from bottom of cliff to first boat (at 25 degree angle of depression - from horizontal)
x2 = distance from bottom of cliff to second boat (at 20 degree angle of depression - from horizontal)
d = x2 - x1 = distance boats are apart from each other (m)
h = height of cliff from water surface = 200 m
x1 = h/[tan(25o)] = (200 m)/(0.4663) = 428.9 m
x2 = h/[tan(20o)] = (200 m)/(0.3640) = 549.5 m
d = x2 - x1 = 549.5 m - 428.9 m = 120.6 m apart
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