Question

b) If-
(√36x+1 +6√x)/(√36x+1 -6√x)=9
Find the value of x.
​

Answer 1

Question :-

If ,

(√(36x)+1 +6√x )(√(36x)+1-6√x)= 9

then find the value of "x".

Answer :-

→ x = 4/9

To find :-

→ Value of x

Formula used :-

( in second method )

→ a² - b² = (a+b)(a-b)

Explanation :-

(First method )

We have ,

(√(36x)+1 +6√x )(√(36x)+1-6√x)= 9

•.• √(36) = 6

.•.

→ (6√x + 1 + 6√x )(6√x +1 - 6√x) = 9

→ (12√x + 1)(1) = 9

→ 12√x = 9 - 1

→ 12√x = 8

→ 3√x = 2

now ,squaring on both sides,

→ (3√x)² = 2²

→ 9x = 4

→ x = 4/9

\_______________/

(Second method )

We have ,

(√(36x)+1 +6√x )(√(36x)+1-6√x)= 9

we can write it ,

→ {(6√x+1)+6√x)}{(6√x+1)-6√x)}=9

now applying the given formula

→ (6√x+1)² - (6√x)² = 9

opening the whole square ,

→ 36x + 1 + 12√x - 36x = 9

→ 12√x = 8

→ 3√x = 2

taking square on both sides ,

→ 9x = 4

→ x = 4/9

\_________________/

hope it will helps you.

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#BAL

Answer 2

Step-by-step explanation:

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