Math, asked by raja1185, 6 months ago

b) If f'(x) = a sinx + bcosx and f' (0) = 4, f (0) = 3,5 (9) = 5, find f(x)​

Answers

Answered by amansharma264
9

CORRECT QUESTION.

f'(x) = a sin(x) + b cos(x) and f'(0) = 4, f'(0) = 3, f (π/2) = 5 find f(x).

f(x) = a sin x + b cos x.

f'(0) = 4.

put the value of x = 0 in equation we get,

f'(x) = a sin(0) + b cos(0) = 4.

f'(x) = 0 + b = 4.

f'(x) = b = 4. ........(1)

as we know that,

sin (0°) = 0.

cos (0°) = 1.

f(x) = ∫f'(x)dx.

put the value of f'(x) in equation we get,

f(x) = ∫f'(x)dx = ∫(a sin x + b cos x)dx.

f(x) = ∫f'(x)dx = -a cos x + b sin x + c.

put the value of f(0) = 3 in equation we get,

f(0) = -a cos(0) + b sin(0) + c = 3

f(0) = -a + c = 3.  .......(2).

f(π/2) = 5

put the value of x = π/2 in equation we get,

-a cos(π/2) + b sin(π/2) + c = 5.

0 + b + c = 5.

b + c = 5  .............(3).

from equation (1) , (2) and (3) we get,

put the value of b = 4 in equation (3)

4 + c = 5.

c = 1.

put the value of c = 1 in equation (2)

-a + 1 = 3.

-a = 2

a = -2.

value of a = -2, b = 4 and c = 1.

put the value of a , b , c in equation we get,

-(-2)cos x + 4 sin x + 1.

2 cos x + 4 sin x + 1.

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