Question

b) If the fifth term (t) is 18, the common difference (d) is 4, find (i) the first term (11) the tenth term of the sequence. c) If the fourth term (t) is 11, the first term (a) is 5, find the common difference of the sequence. d) If the first term (a) is 6 and the sixth term (t) is 31, find (i) the common difference (ii) the fifth term (iii) the seventh term of the sequence​

Answer 1

Answer:

Since the common difference is 4,the sequence is an arithmetic sequence

Let a be the first term ,d be the common difference,n be the number of terms,

n=5,d=4,5th term=18

nth term=a+(n-1)d

5th term=a+(5–1)*4

18=a+16

a=18–16=2

First term is 2

To find the 10 term

n=10,a=2,d=4

nth term=a+(n--1)d

10 th term=2+(10–1)*4=2+9*4=2+36=38

Answer first term=2

Tenth term=38