Question

b) In an examination, there are three papers, each of 100 marks. A candidate obtained
64 marks in the first paper and 76 marks in the second paper. If he has to get an
overall score of 80%, how many marks does he need to score in the third paper?
Our​

Answer 1

Each paper is of 100 marks.

There are 3papers so 300marks.

80% of 100 marks

=80marks

hence,80% of 300marks is 240marks.

76+64=140

240(to pass)-140marks

Now,he has to score 100marks that means full marks to pass in his exam.

Answer 2

Answer:

Total marks =100+100+100=300

Let x marks obtained by the candidate in third paper

Marks obtained by the candidate in second paper =75

Mark obtained in first paper =53

Total marks obtained by the candidate =53+75+x−128+x

ACQ,

⇒(

300

128+x

)×100=70

⇒128+x=3×70

⇒x=210−128

⇒x=82