Question

B
In the adjacent figure,
AC = 6 cm, AB = 5
cm and ZBAC =
30°. Find the area of
the triangle
5 cm
30°
A
С
6 cm​

Answer 1

AC = 6 cm ,

AB = 5 cm

<BAC = 30°

Draw BD perpendicular to AC

In ∆ ADB ,

Sin 30° = BD/AB

=> 1/2 = BD/5

=> BD = 5/2 cm

Now ,

Area of the ∆ABC = ( 1/2 )×base×height

= (1/2) × AC × BD

= ( 1/2 ) × 6cm × ( 5/2 ) cm

= ( 15/2 ) cm²

= 7.5 cm²

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