Question

(b) In the figure given below, ABDC is a cyclic quadrilateral in w
(i). IF BAD = 52° BCA = 35º, find | ACX
(it). P.T|CBD = |ADB. Also P.T DY = BY
(iii). Prove that XA = XC.
52
(
1) B(03) and C(-2,1) are the three ve​

Answer 1

Answer:

Given: CB = CD and ∠CBD = 35°

Consider ΔBCD

Here,

CB = CD (given)

∠CBD = ∠CDB = 35° (In a triangle, angles opposite to equal sides are equal)

By angle sum property

∠BCD + ∠CBD + ∠CDB = 180°

∠BCD + 35° + 35° = 180°

∠BCD = 180° – 35° – 35° = 110°

We know that,

In a cyclic quadrilateral opposite angles are supplementary

∴ ∠BCD + ∠BAD = 180°

110° + ∠BAD = 180°

∠BAD = 180° – 110° = 70°

∴ ∠BAD = 70°

Step-by-step explanation: