Question

(b) In the figure , two tangents PA and PB are drawn to a Circle with centre O from an external point P. The
find the angle APB
angle BAO =50°​

Answer 1

Answer:

PA=PB

∆PAB=50

∆PBA=∆PAB

∆PBA=50

∆PBA+∆PAB+∆APB=180

∆APB=180-100=80

∆AOB+∆APB=180

∆AOB=180-80

∆AOB=100