Question

sin theta+cos theta÷sin theta-cos theta+sin theta-cos theta÷sin theta+cos theta=2÷1-cos²theta
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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Given, 2sin2θ−cos2θ=2

⇒2sin2θ−1+sin2θ=2

⇒3sin2θ−1=2

⇒sin2θ=1

⇒sinθ=sin900

⇒θ=90∘

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