Question

b) In the given figure ABCD, AD = BC ; AD || BC. Prove that AADC = ACBA and
hence show that AB = CD
A
B
D
С​

Answer 1

Answer:

From figure, AB = CD and AD = BC. To prove: ΔADC ≅ ΔCBA Consider Δ ADC and Δ CBA. AB = CD [Given] BC = AD [Given] And AC = AC [Common side] So, by SSS congruence criterion, we have ΔADC≅ΔCBA

Hence proved.