B is 40% less efficient than A and efficiency of C is 1/4 th the efficiency of A and B together. If C joined A and
B every third day then all three together complete the work in 27(3/4) days. Find in how many days will B
alone complete the work?
1.40days
2.60days
3.50days
4.100 days 5.80days
Answers
B alone will complete in 80 Days
Step-by-step explanation:
Let say A's 1 Day work = A
then B's 1 Day work = A - (40/100)A = 0.6A
C's 1 Day work = (A + 0.6A)/4 = 0.4A
C joined A and B every third day then all three together complete the work in 27(3/4) days
=> A & B worked each for 27 3/4 = 111/4 Days
C worked for 9 days
Total Work done = A(111/4) + (0.6A)(111/4) + 0.4A * 9
= 0.4A * 120
= 48A
B's 1 Day work = 0.6A
days B will alone complete the work = 48A/(0.6A) = 80 Days
B alone will complete in 80 Days
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Answer:
80days
Step-by-step explanation:
B's 40% less efficient than A
then A:B = 100:60 = 5:3
C's efficiency 1/4 th of (A+B) then efficiency of C = 2
Now every third day C joined for work so C work for 9days (27/3) whereas A & B both work for 27 3/4 days.
So Total Work (eff * Time) = 111/4 * 5 + 111/4 * 3 + 9*2 = 240
then Total Work done by B = 240/3 = 80 days