Question

B” is 50% faster than “A”.
 A” starts at 10 A.M. and “B” starts at 12 P.M. “A” travels at a speed of 60 km/hr. 
 If “A” and “B” are 420 kms apart, the time when they meet when they travel in opposite direction is?

Answer 1

{some corrections in question}

Question : B is 50 % faster than speed of A. A starts moving at 10 AM and B starts moving at 12 PM. A travels at a speed of 60 km/hr. If A and B are 420 km apart, what the time when they meet when they travel in opposite direction is ? {Facing each other face or start moving toward each other}

Given data :

⟹ speed of B is 50 % faster than A

⟹ A starts moving at 10 AM and B starts moving at 12 PM

⟹ speed of A = 60 km/hr

⟹ A and B are 420 km apart.

To find : What the time when they meet when they travel in opposite direction is ?

Solution : according to given data;

⟹ B = A + 50 % ----{ 1 }

Now, we have to find 50% of the speed of A,

Let, 50 % speed of A be x

⟹ {x/speed of A} * 100 = 50

⟹ {x/60} * 100 = 50

⟹ x/60 = 50/100

⟹ x/60 = 0.5

⟹ x = 60 * 0.5

⟹ x = 30

Hence, 50 % of the speed of A is 30 km/hr

[From eq. { 1 }]

⟹ B = A + 30

⟹ B = 60 + 30

⟹ B = 90 km/hr

Hence, speed of B is 90 km/hr.

According to given data, A starts moving two hours before than B.

So now, to find distance coveres by A in two hour.

⟹ speed of A = distance/time

⟹ 60 = distance/2

⟹ distance = 60 * 2

⟹ distance = 120 km

Now, {ATQ, total distance = 420 km}

⟹ Remaining distance = Total distance - distance covered by A in 2 hour

⟹ Remaining distance = 420 - 120

⟹ Remaining distance = 300 km

After traveling 2 hour by A, A and B start moving at 12 PM.

Now, to find the time when A and B meet

⟹ speed of A and B = Remaining distance/time

⟹ 60 + 90 = 300/time

⟹ 150 = 300/time

⟹ time = 300/150

⟹ time = 2 hour

Hence A and B meet after 2 hour.

Answer : Therefore A and B meet at 2 PM.

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Answer 2

Answer:

hope it helps you have a nice day