Question

B is as more younger than C as he is elder than A. Ratio of ages of A to C is 5 : 9. If B’s age after 10 years will be 24, find the average of all of their present ages.

Answer 1

Answer: 14 years

#bal

Step-by-step explanation:

B’s present age = 24-10 = 14

So C’ age = 14+x

And A’ age = 14-x

(14+x)/(14-x) = 9/5

Solve, x = 4

So average age = (10+14+18)/3 = 14 years

Answer 2

The average of all of their present ages is 17.73 years.

Step-by-step explanation:

Let the age of A be 5x

Let the age of C be 9x

Since B is as more younger than C as he is elder than A.

Since C is elder than A is given by

$9x-5x=4x$

According to question, we get that

$C-B=C-A\\\\9x-B=9x-5x\\\\9x-B=4x\\\\9x-4x=B\\\\5x=B$

If B’s age after 10 years will be 24

Age of B = 24-10=14 years

So, 5x = 14

$x=\dfrac{14}{5}$

C's age is given by

$9x=9\times \dfrac{14}{5}=\dfrac{126}{5}=25.2$

So, Average of all of their present age would be

$\dfrac{9x+5x+5x}{3}=\dfrac{19x}{3}=\dfrac{19}{3}\times \dfrac{14}{5}=\dfrac{266}{15}=17.73$

Hence, the average of all of their present ages is 17.73 years.

# learn more:

If B is 2 yeaes elder than A and B is 1 years younger than C if their average is 24 than find the age of C

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