Question

(b) PQRS in which PQ = 6 cm, QR = 4 cm, P = 45°, ZQ = 115º and ZS = 95°. [Hint. Find ZR using ZR = 360° - (ZP + ZQ + ZS)] -​

Answer 1

Answer:

Steps of Construction:

(i) Construct a line segment QR = 6 cm.

(ii) At the point Q, construct a ray QX making an angle of 90

⋅

and cut off QP = 4 cm.

(iii) At the point P, construct a ray making an angle of 60

⋅

and at R, a ray making an angle 120

⋅

which meets each other at the point S.

Therefore, PQRS is the required quadrilateral.

Answer 2

Question: (b) PQRS in which PQ = 6 cm, QR = 4 cm, P = 45°, ZQ = 115º and ZS = 95°. [Hint. Find ZR using ZR = 360° - (ZP + ZQ + ZS)] -

Answer:

Given above ☝

Step-by-step explanation:

Given above ☝

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