Question

ब) सोडवा
4
1) जर दोन संख्यांमधील फरक 36 आहे,एक संख्या दुसरीच्या 4 पट आहे
तर त्या संख्या शोध​

Answer 1

Answer:

Let, numbers be X and Y

By the 1st condition,

X - Y = 36................1

By the 2nd condition,

X = 4×Y

X - 4Y = 0 ..................2

Subtracting eqn 2 from eqn 1,

X - Y = 36

-

X - 4Y= 0

- +. -

3Y= 36

Y= 36

3

Y= 12

Now,

Substituting ( Y=12 ) in eqn 1,

X - Y = 36

X - 12= 36

X = 36+12

X = 48

Therefore , the numbers are 48 and 12.

I hope it will help you.......