b selling a bucket for rupees 67.50 a shopkeeper loses 10% .How much percent would he gain or loss by selling it for rupees 82.50
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According to the given problem,
SP = 67.50
LOSS % = 10
( Ratio and percentage method)
______________________________
If we express this in ratio, we'll get
SP/CP = 90/100 ( let CP be 100).
From the above ratio,
We can say that 90 unit = 67.50 rupees.
Then, 100 unit = (67.50/90) × 100 rupees = 75 rupees.
Hence, The CP is 75 rupees.
If CP is 75 rupees and the SP is 82.50, Gain is incurred (SP>CP).
Gain = ( 82.50 - 75) = 7.50 rupees.
Gain% = ( Gain / CP) ×100
= ( 7.50 / 75) ×100
= 10%
I hope this answers your question sufficiently. Happy learning.
SP = 67.50
LOSS % = 10
( Ratio and percentage method)
______________________________
If we express this in ratio, we'll get
SP/CP = 90/100 ( let CP be 100).
From the above ratio,
We can say that 90 unit = 67.50 rupees.
Then, 100 unit = (67.50/90) × 100 rupees = 75 rupees.
Hence, The CP is 75 rupees.
If CP is 75 rupees and the SP is 82.50, Gain is incurred (SP>CP).
Gain = ( 82.50 - 75) = 7.50 rupees.
Gain% = ( Gain / CP) ×100
= ( 7.50 / 75) ×100
= 10%
I hope this answers your question sufficiently. Happy learning.
nikunj551:
this is not right answer
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