Question

b).Show that tan5' tan25' tan30° tan65º tan85' =1/√3​

Answer 1

Answer:

Step-by-step explanation:

LHS

$tan 5^{0} * tan 25^{0} * tan 30^{0} * tan 65^{0} * tan 85^{0}$

= $tan 5^{0} * tan 25^{0} * tan 30^{0} * cot 25^{0} * cot 5^{0}$

= $tan 5^{0} * tan 25^{0} * tan 30^{0} * \frac{1}{tan 25^{0} } * \frac{1}{tan 5^{0} }$

= $tan 30^{0}$

= $\frac{1}{\sqrt[]{3} }$

= RHS

Hence proved...

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