B takes 4 times as long as A and C together and C takes thrice as long as A and B
together to complete the work. If A, B and C together complete the work in 20 days,
how long would B alone take to complete the work?
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Answer:
96 days
Step-by-step explanation:
Let B and C together do the job in x days. So, A does the job in 3x days.
So, A + B + C together do the job in 1 day 1/3x + 1/x = 4/3x part.
Again, A+ B+C do in 1 day 1/24 part of the job
So, 4/3x = 1/24 Or, x = 32
So, A does the job in 3 * 32 = 96 days Ans.
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