Question

(b) tan theta + tan 3theta = 2 tan 2theta.​

Answer 1

Answer:

is rejected when n is odd as it makes ∞=∞.

∴θ=nπ as it will make 0=0.

Step-by-step explanation:

tan3θ+tanθ=2tan2θ

tan3θ−tan2θ=tan2θ−tanθ

cos3θcos2θ

sin(3θ−2θ)

=

cos2θcosθ

sin(2θ−θ)

or sinθ(cosθ−cos3θ)=0

or sinθ⋅2sinθsin2θ=0

∴sinθ=0, ∴θ=nπ

sin2θ=0, ∴2θ=nπ or θ=

2

nπ

But θ=

2

nπ

is rejected when n is odd as it makes ∞=∞.

∴θ=nπ as it will make 0=0.