बिंदु (-1,1)की रेखा 12 (x+6) = 5 (y-2) से दूरी ज्ञात कीजिए
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हल :
रेखा का समीकरण : 12(x + 6 ) = 5 ( y - 2 )
या 12 x + 72 = 5y - 10 या 12x - 5y + 82=0
अतः बिंदु (-1,1) कि उक्त रेखा से दूरी
| 12×(-1)-5×1+82| | - 12 - 5 +82 |
_________________=__________________
√ 12² + (-5)² √144 + 25
= 65. 65
_____ = _____ = 5 इकाई
√169. 13
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