Question

बिंदूA(2, -2) तथा बिंदू B(-1, y) केबीच की दूरुी 5 हो, तो y का मान ज्ञात कीजीए l​

Answer 1

Step-by-step explanation:

$\\ \sf\longmapsto \sqrt{( - 1 - 2) {}^{2} + (y + 2) {}^{2} } = 5 \\ \\ \sf\longmapsto \sqrt{( - 3) {}^{2} + {y}^{2} + 4y + 4 = } = 5 \\ \\ \sf\longmapsto \sqrt{9 + {y}^{2} + 4y + 4 } = 5 \\ \\ \sf\longmapsto {y}^{2} + 4y + 13 = 25 \\ \\ \sf\longmapsto {y}^{2} + 4y = 25 - 13 \\ \\ \sf\longmapsto {y}^{2} + 4y = 12 \\ \\ \sf\longmapsto {y}^{2} + 4y - 12 = 0 \\ \\ \sf\longmapsto {y}^{2} - 6y + 2y - 12 = 0 \\ \\ \sf\longmapsto y(y - 6) + 2(y - 6) = 0\\ \\ \sf\longmapsto (y - 6)(y + 2) = 0 \\ \\ \bf\longmapsto y = 6 \: or \: y = - 2$