Question

बंदूक से 12g की गोली दागी जाती है, गोली की
बैरल से बाहर निकलने में 0.06 s लगते हैं तथा
उसकी गति 600 m/s है। बंदूक द्वारा गोली पर
आरोपित बल कितना होगा?​

Answer 1

Answer:

force=magnitude÷mass

Answer 2

The force changed will be equal to 120 N.

Explanation:

Gun shoots 12g

It takes 0.06 s to exit the barrel and

Its speed is 600 m / s. Gun shot

What will be the force charged?

It is given that,

Mass of the bullet, m = 12 g = 0.012 kg

Initial speed of the bullet, u = 0 (at rest)

Final speed of the bullet, v = 600 m/s

Time taken to exit the barrel, t = 0.06 s

We need to find the force changed. It can be calculated using second law of motion. Force is equal to the product of mass and acceleration as :

F = ma

$F=0.012\times \dfrac{600}{0.06}$

F = 120 N

So, the force changed will be equal to 120 N. Hence, this is the required solution.

Learn more

Second law of motion

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