Physics, asked by nissam, 10 months ago

(b) The equation for such a wave is
y = 4sint (2t-0.01x) where x and y
are in cm and t in seconds.
Find its (i) amplitude
(ii) wavelength
(iii) initial phase and (iv) frequency

Answers

Answered by harsharora111

3

Answer:

Amplitude = 4cm

k = .01

k = 2π/lemda

Lemda = 2π/.01 = 200π

3) t =0

phase is Kx = 0.01x

w = 2

2 = 2πf

f = 1/π

Any doubt inbox

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