Question

b)The lactic acid concentration in the blood of the athlete was measured at intervals.At the end of the slow run the lactic acid concentration had increased by 30%.After a rest, the athlete ran at a much faster speed on the treadmill. At the beginning of thisexercise the lactic acid concentration in his blood was 100 mg dm–3. After 11 minutes runningat the faster speed, his lactic acid concentration was 270 mg dm–3.(i)Calculate the percentage increase in lactic acid concentration at the end of the fasterrun.Show your working.



(ii)Explain why the percentage increase in lactic acid is much greater when running at thefaster speed.

Answer 1

Answer:

or do je dh HDD USC usb usb usb usb much kuch kuch kuch

Answer 2

Answer:

170

Explanation:

170 divided by 700 times 100 = 170%