b. The nth term of an A.P. is given by (- 4n +15) Find the sum
of first 20 terms of this A.P.
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a1 = -4 × 1 + 15 = 11
a2= -4 × 2 + 15 = 7
so , d = a2 - a1
= 7 - 11 = -4
Now
S 20 = 20/2 [2 × 11 + (20-1) -4]
= 10 [ 22 - 76 ]
= 10 ×[-54]
= -540. Hope it helps you
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