Math, asked by tanishachoudhary73, 5 months ago

(b) The scores of Asha and Bhanu in an examination
are in the ratio 13 : 16. After they applied for
revaluation, their scores increased by the same
amount and their new scores are in the ratio 52 : -
61. The ratio of the scores of Asha before and
after revaluation is
(A) 2:3 (B) 3:4 (C) 4:5
(D) 5:6​

Answers

Answered by knjroopa
4

Step-by-step explanation:

Given The scores of Asha and Bhanu in an examination are in the ratio 13 : 16. After they applied for  revaluation, their scores increased by the same  amount and their new scores are in the ratio 52 : 61. The ratio of the scores of Asha before and  after revaluation is

  • Let the scores of Asha and Bhanu be m. So we get the scores as 13m and 16 m. So the scores increases by n, so we have,
  •            (13m + n)/(16m + n) = 52/61          
  • So 13m + n / 16m + n = 52 / 61
  • 61(13m + n) = 52(16m + n)
  • 793 m + 61n = 832m + 52n
  • 61n – 52n = 832 m – 793 m
  •       9n = 39 m
  • Or n = 39 m / 9
  •      n = 13 m / 3
  • Now Asha’s new score is 13m + 13 m / 3
  •                                               = 39 m + 13m / 3
  •                                               = 52m / 3
  • Therefore the required ratio before and after revaluation will be
  •                                                    is 13 m / 52 m / 3
  •                                                     = 13m x 3 / 52 m
  •                                                     = ¾
  •                                                    = 3 : 4

Reference link will be

https://brainly.in/question/2164896

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