Question

(b) Two electric bulbs rated 100 W; 220 V and 60 W; 220 V are connected in parallel to an electric main of 220 V. Find the current drawn by the bulbs from the mains.

Answer 1

Answer:

$\frac{1}{100} + \frac{1}{60} = \frac{1}{r \: eqv} \\ \frac{3 + 5}{300} = \frac{8}{300} = \frac{2}{75} \\ reqv \: \frac{75 }{2} = 67.5$

here is your answer

Answer 2

Answer:

I=8/11A

Explanation:

P1=V×I1

100=220×I1

5/11=I1           ----------------(1)

P2=V×I2

60=220×I2

3/11=I2          ----------------(2)

Ip=I1+I2

Ip=8/11A=0.73A