Question

(b) When 3 is subtracted from a number y, the result is 7.
(c) The difference of a number p and 6 is 13 when p > 6.
(d) Twice of a number x is 6.
(e) One-fifth of a number z is 1.
(f) Two-sevenths of a number p is 3.
(g) A number is 1 less than twice of 9.
(h) Three times a number is 2 more than 5.
(i) When 9 is subtracted from twice a number, we get 3.
) The difference of of y and 1 is zero.
MPOSITE MATHEMATICS​

Answer 1

SOLUTION

TO DETERMINE

(b) When 3 is subtracted from a number y, the result is 7.

(c) The difference of a number p and 6 is 13 when p > 6.

(d) Twice of a number x is 6.

(e) One-fifth of a number z is 1.

(f) Two-sevenths of a number p is 3.

(g) A number is 1 less than twice of 9.

(h) Three times a number is 2 more than 5.

(i) When 9 is subtracted from twice a number, we get 3.

(j) The difference of of y and 1 is zero.

EVALUATION

(b) When 3 is subtracted from a number y, the result is 7.

Hence the required equation is

$\sf{y - 3 = 7}$

(c) The difference of a number p and 6 is 13 when p > 6.

Hence the required equation is

$\sf{p - 6 = 13}$

(d) Twice of a number x is 6.

Hence the required equation is

$\sf{2x = 6}$

(e) One-fifth of a number z is 1.

Hence the required equation is

$\displaystyle \sf{ \frac{1}{5}z = 1}$

(f) Two-sevenths of a number p is 3.

Hence the required equation is

$\displaystyle \sf{ \frac{2}{7} p = 3}$

(g) A number is 1 less than twice of 9.

Let x be the variable

Hence the required equation is

$\displaystyle \sf{x = (2 \times 9) - 1}$

(h) Three times a number is 2 more than 5.

Let x be the variable

Hence the required equation is

$\displaystyle \sf{3x = 2 + 5 }$

(i) When 9 is subtracted from twice a number, we get 3.

Let x be the number

Hence the required equation is

$\displaystyle \sf{2x - 9 = 3}$

(j) The difference of y and 1 is zero.

Hence the required equation is

$\displaystyle \sf{y - 1 = 0}$

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