Question

B1, B2 and B3 are three identical bulbs connected as shown in Figure When all the three bulbs glow, a current of 3A is recorded by the ammeter A. (i) What happens to the glow of the other two bulbs when the bulb B1 gets fused? (ii) What happens to the reading of A1, A2, A3 and A when the bulb B2 gets fused? (iii) How much power is dissipated in the circuit when all the three bulbs glow together?

Answer 1

Hy mate
 (i) Other bulbs will glow with same brightness. 

 (ii) When the bulbs are in parallel, wattage will be added (4.5 W) and the ammeter reading would be 

4.5W/4.5v=1.0 ampere

(iii) Since ammeter reading is 0.1 ampere, resistance of the combination is=4.5V/1.0A=4.5


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Answer 2

⛦Hᴇʀᴇ Is Yoᴜʀ Aɴsᴡᴇʀ⚑
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(i) When bulb B1 gets fused, the currents in B2 and B3 remain same I2 = I3 = 1A.

So, their glow remains unaffected.

(ii) When bulb B2 gets fused, the current in .B2 becomes zero and currents in B1 and B3 remains 1 A.

Total current I = I1 + I2 + I3
= I + 0 + I = 2A

♦Current in ammeter A1 = 1 A
♦Current in ammeter A2 = 0
♦Current in ammeter A3 = 1 A
♦Current in ammeter A4 = 2A

_________
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