Math, asked by hiteshleo9543, 10 months ago

B2-4ac=(2k+6)2-4(k+1)(k+8)

Answers

Answered by vickykumargd81
1

Answer:

B2-4ac=(2k+6)-2(ksuq.+1)(9)

B2-4ac=-4k-12+9k suq.+9

B2-4ac=9k suq.+4k-3

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