B2H6+2NH3 gives which product ?
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B2H6 + 2NH3 → B2H6.2NH3
diborane combine first in B2H6.2NH3
then
convert borazole or inorganic benzene
e.g
3 B2H6.2NH3 → 2B3N3H6 +12 H2
here B3N3H6 is known as inorganic benzene
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