Cos theta +sin theta=√2 . Then prove cos theta-sin theta=√2sin theta
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Let θ = x
cos x + sin x = √2 cos x
squaring on both side, we get......
cos2x + sin2x + 2cosxsinx = 2cos2x
2sinxcosx = 2cos2x - cos2x - sin2x
2sinxcosx = cos2x - sin2x
2sinxcosx = (cosx+sinx) (cosx - sinx)
2sinxcosx = (root2 cosx) (cosx - sinx)
2sinxcosx/root2 cosx = cosx - sinx
√2 sinx = cosx - sinx
simimehta2003:
Thanx!!
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