Question

babu is 24 years older than varun 10 years back babu's age was five times the age of varun find their present age

Answer 1

let us keep varun's age as x

so, babu's age will be x + 24

10 years back,

so,

varun = x - 10

babu =  x + 24 - 10 = x + 14

varun' s age 5 times = 5 (x-10) = 5x - 50

so,

5x - 50 = x = 14

= 5x - x = 14 + 50

= 4x = 64

= x = 16

therfore their present ages would be,

varun = x = 16 years

babu = x + 24 =16 + 24 = 40 years

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Answer 2

Answer:

Step-by-step explanation:

Let seven years, age of Swati was x years and age of Varun was 5x² years

Present age of Swati = ( x + 7 ) years

Present age of Varun = ( 5x² + 7 ) years

Given, after 3 years swati's age will be 2 / 5 of Varun's age.

Age of Swati after 3 years = ( x + 7 + 3 ) years = ( x + 10 ) years

Age of Varun after 3 years = ( 5x² + 7 + 3 ) years = ( 5x² + 10 ) years

Given, age of Swati after 3 years = age of varun after 3 years

( x + 10 ) = 2 / 5 × ( 5x² + 10 )

( x + 10 ) = 2( x² + 2 )

x + 10 = 2x² + 4

2x² - x + 4 - 10 = 0

2x² - x - 6 = 0

2x² - 4x + 3x - 6 = 0

2x( x - 2 ) + 3( x - 2 ) = 0

x = 2 [ Age can't be negative ]

Therefore,

present age of Swati = ( 2 + 7 ) = 9 years

present age of Varun = 5(2)²+7=27 years

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