bag contains 10 white and 3 black balls. Balls are drawn one by one without replacement till all the black balls are drawn. Find the probability that all black balls are drawn by the 6thdraw.
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Solution:
By Hypergeometric Distribution:
where k=6 , M=13 , n=3, x=3
P[all blacks]= ((k taken x)(M-k taken n-x))/(M taken n)
P[all blacks]= ((6 taken 3)(13-6 taken 3-3))/(13 taken 3)
P[all blacks]= ((6 taken 3)(7 taken 0))/(13 taken 3)
P[all blacks]= ((20)(1))/(286)
P[all blacks]= 0.0699
Therefore, by heypergeometric distribution the probability that all black balls are drawn by the 6th draw is 0.0699.
By Hypergeometric Distribution:
where k=6 , M=13 , n=3, x=3
P[all blacks]= ((k taken x)(M-k taken n-x))/(M taken n)
P[all blacks]= ((6 taken 3)(13-6 taken 3-3))/(13 taken 3)
P[all blacks]= ((6 taken 3)(7 taken 0))/(13 taken 3)
P[all blacks]= ((20)(1))/(286)
P[all blacks]= 0.0699
Therefore, by heypergeometric distribution the probability that all black balls are drawn by the 6th draw is 0.0699.
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