Question

Bag contains 5 red 7 green and 4 white balls 3 balls are drawn one after the other without replacement find the probability that the ball drawn of white green and green respectively

Answer 1

probability for white ball=4/16=1/4
now balls left=15
probability for 1st green ball=7/15
now balls left=14
probability for 2nd green=6/14=3/7
I HOPE IT WILL HELP YOU

Answer 2

1) Number of red balls = 5

Green balls = 7

White Balls =  4

Total balls = 16

2) At first take, probability of taking a white ball = 4/16 = 1/4

3) Remaining balls after first take =  15

Red = 5,

Green  = 7

White = 3

Probability of getting green ball = 7/15

4) Remaining balls after second take =  14

Red = 5,

Green  = 6

White = 3

Probability of getting green ball = 6/14 = 3/7

5) Total probability = 1/4 * 7/15 * 3/7 = 1/20