Bag i contains 3 red and 4 black balls and bag ii contains 4 red and 5 black balls. One ball is transferred from bag i to bag ii and then a ball is drawn from bag ii. Find the probablity of color of ball drawn from bag ii
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no.of balls in bag i is 3+4 =7
no.of balls in bag ii is 4+5 =9
when 1 ball is put into bag ii from bag i no. of balls in bag ii is 10.
so when one ball is drawn out n(a)=1 and n(s)=10
so,p(a)=n(a) /n(s)
p(a)=1/10
no.of balls in bag ii is 4+5 =9
when 1 ball is put into bag ii from bag i no. of balls in bag ii is 10.
so when one ball is drawn out n(a)=1 and n(s)=10
so,p(a)=n(a) /n(s)
p(a)=1/10
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