Math, asked by nutanpatel218, 5 months ago

Bahupad p(x) ko g(x) se bhag dijiye jabki
P(x) =2x²-7x-3,g(x)=x=1
P(x)=5x³-2x²+x-3,g(x)=x+2​

Answers

Answered by Cive
1

Answer:

p(x) = 2x²-7x -3

g(x) = x = 1

substituting x in p(x)

=> 2 x 1²-7 x 1 -3

=2- 7 -3 =>-8

p(x) = 5x³- 2x² + x- 3

g(x) = x + 2 >>> x= -2

substituting x in p(x)

=>5 x -2³ -2 x (-2)² -2 -3

=>5 x -8 -8 -5 = -53

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